MPP Experiment 3

16-BIT DIVISION IN 8086

.MODEL SMALL

.STACK 100H

DATA SEGMENT
NUM1 DW 4567H,2345H
NUM2 DW 4111H
QUO DW 2 DUP(0)
REM DW 1 DUP(0)
DATA ENDS
CODE SEGMENT
ASSUME CS:CODE,DS:DATA
START: MOV AX,DATA
MOV DS,AX
MOV AX,NUM1
MOV DX,NUM1+2
DIV NUM2
MOV QUO,AX
MOV REM,DX
INT 21H
CODE ENDS
END START

INPUT:     Dividend - 23454567,
           Divisor - 4111,
OUTPUT:    AX – 8AC5H (quotient);
           DX – 0952H (reminder);

16-BIT MULTIPLICATION IN 8086

.MODEL SMALL

.STACK 100H

DATA SEGMENT

NUM1 DW 1234H

NUM2 DW 1234H

LSB DW 2 DUP(0)

MSB DW 1 DUP(0)

DATA ENDS

CODE SEGMENT

ASSUME CS:CODE,DS:DATA

START: MOV AX,DATA

MOV DS,AX

MOV AX,NUM1

MOV DX,NUM2

MUL DX

MOV LSB,AX

MOV MSB,DX

HLT

CODE ENDS

END START

INPUT:     NUM1- 1234,
                 NUM2- 1234,
OUTPUT:    AX – 5A90H (LSB);
           DX – 014BH (MSB);

8-BIT DIVISION IN 8086

.model small

.stack 100h

assume cs:code, ds:data

data segment

num1 dw 99h

num2 dw 33h

data ends             

code segment

START: mov ax,data

mov ds,ax

mov ax,num1

mov bx,num2

div bx

int 21h

code ends

end start

INPUT:  NUM1- 99,

              NUM2- 33,

OUTPUT: AX- 0003

8-BIT MULTIPLICATION IN 8086

.model small

.stack 100h

assume cs:code, ds:data

data segment

num1 dw 56h

num2 dw 78h

data ends             

code segment

START: mov ax,data

mov ds,ax

mov ax,num1

mov bx,num2

mul bx

int 21h

code ends

end start

INPUT:  NUM1- 56,
              NUM2- 78,
OUTPUT: AX- 2850

NOTE: The code for 16-bit division is 100% correct and tested. It is very likely that sir might question you about how the num1+2 instruction is executed, so be prepared!!

Here are the algorithms and flowcharts for 16-bit multiplication and 16-bit division codes:

CLICK HERE TO DOWNLOAD!